sin60° as a fraction - The Student Room
2024年5月22日 · sin (A+B)=sin A cos B + cos A sin B sin 60°= sin (30°+30°) = sin 30° cos 30° + cos 30° sin 30° = 2 sin 30° cos 30° = 2 (1/2) ((√3)/2) = (√3)/2 Well if you know that cos30 = root(3)/2 then you can just use: sin(90 - x) = cosx which incidently is …
Sin 30° - cos 30°/sin 60°? - Socratic
2018年5月13日 · cos 30^circ = sin 60^circ because they're complementary angles, so this is sin 30^circ - {cos 30^circ} /{ sin 60^circ} = sin 30^circ - 1 = 1/2 - 1=-1/2 # Yet another 30/60/90 question. Get new a triangle people! I'll assume this is \\sin 30^circ - cos 30^circ /sin 60^circ I'm never really sure because many students forget to add parentheses around the numerator and denominator when typing in a ...
How do you find the value of sin 60? - Socratic
2018年4月25日 · How do you find the value of #sin 60#? Trigonometry Right Triangles Trigonometric Functions of Any Angle ...
What is sin 120 degrees? - Socratic
2015年5月30日 · On the trig unit circle: sin 120 = sin (180 - 60) = sin 60 = sqrt3/2
How do I find the value of sin 300? - Socratic
2015年9月11日 · We have that #sin300=sin(360-60)=sin360*cos60-cos360*sin60=0-sin60=-sqrt3/2# Answer link. Related questions.
How do you find the exact value of sin 105 degrees? - Socratic
2015年10月25日 · Find exact value of sin (105) Ans: (sqrt(2 + sqrt3)/2) sin (105) = sin (15 + 90) = cos 15. First find (cos 15). Call cos 15 = cos x Apply the trig identity: cos 2x = 2cos^2 x - 1. cos 2x = cos (30) = sqrt3/2 = 2cos^2 x - 1 2cos^2 x = 1 + sqrt3/2 = (2 + sqrt3)/2 cos^2 x = (2 + sqrt3)/4 cos x = cos 15 = (sqrt(2 + sqrt3)/2. (since cos 15 is positive) sin (105) = …
What is #tan(45)#, #sin(45)# and #cos(45)#? - Socratic
2017年11月17日 · What are the basic properties of a 30-60-90 triangle? How do the Special Right Triangles relate to the Unit Circle? How do you find the other two side of a right triangle ABC, if #∠B=60# and #AB=12# where AB is...
How do you find the value of csc 60? - Socratic
2015年6月8日 · csc 60 = 1/sin 60 Trig conversion table gives-> sin 60 = (sqrt3)/2 csc 60 = 2/(sqrt3) = (2sqrt3)/3
How do you find the six trigonometric functions of 300 degrees?
2015年5月25日 · Use the trig unit circle as proof. sin 300 = sin (-60 + 360) = sin (-60) = -sin 60 = (-sqrt3)/2 cos 300 = cos (-60 + 300) = cos 60 = 1/2 tan 300 = (-sqrt3)/2 : (1/2 ...
How do you find the value of sin 240? - Socratic
2015年10月17日 · Trig unit circle --> sin (240) = sin (60 + 180) = - sin 60. Trig Table of Special Arcs --> #- sin 60 = - sqrt3/2#